essentials-home-brew-xl

Essentials for a Quality Brewing Experience

Knowing exactly how to brew beer isn’t something that most of us know. As a matter of fact most of us know nothing about brewing or what it entails. It isn’t easy being a master brewing and knowing the exact amount of ingredients to put into each batch.

In the last few years the popularity of brewing has exploded, brewers throughout the country have started brewing hundreds of different batches of brews at home and knowing how to brew is an extremely important part of the process. It all starts with good quality material and products. You can’t brew without having any idea of what to add into your brew or what to take away from it.

Brewing is a process of love and having the tools for it can make it a much better experience. Think of gardening, it is challenging and yet extremely rewarding. Same for brewing.

If you’re interested in starting brewing I would advise you to get some of the best brewing stuff out there. The first one would be a thermometer designed for brewing that can help you know when you beer is done or not. Without one of these there is no exact way to determine that your brew is done. The second part of that is putting it into a canonical fermenter or another device that is designed specifically for brewing. These aren’t expensive but they also aren’t cheap either.

If you’re serious about brewing I would suggest getting one that is higher quality and not being cheap about the material. This will let you brew better quality beers for longer in the future and not have to worry about things like contamination.

 

essentials-home-brew-xl

線上骰子機率基本介紹

Casino in Taiwan

今天OnlineCasinoTW線上賭博網站主要介紹花旗骰與骰寶中的骰子。骰子是最早的賭博用具之一。骰子自然都是立方體,每一面上都有若干點,其點數分別為1、2、3、4、5和6。相對兩面上的點數之和均為7,這樣骰子的6個面可以分為三對,即1與6、2與5、3與4。

骰子常常是已成對擲出,以便得到一個期望的值。首先假設骰子是”公平”的,這樣擲出時每一面都有1/6的機率。而為了計算某一總點數出現的機率,我們必須找出有多少種情形可以得到這一總點數。然後我們把這個數字除以36,即骰子對的總數(注意必須把兩個骰子區別開來)。
想像一個骰子是紅色而另一個骰子是藍色有助於理解問題。比如說12這個總點數只能有一種情形,即紅色骰子擲出6點,而藍色骰子也需擲出6點。因此總點數為12出現的概率為1/36。另外,總點數為11可以有兩種情形得到,即紅色骰子擲出6點,藍色骰子擲出5點,或者紅色骰子擲出5點,藍色骰子擲出6點。這樣總點數為11出現的概率為2/36,即1/18。擲出11點的可能性為擲出12點的可能性的兩倍。另外一個問題是,這一理論將導致一個不可靠的結論,即兩個骰子擲出某一總點數一不管是多少一的概率小于1